Understanding implied odds postflop
Content by Tools of Poker Methodology and calculation assumptions
What does this calculation help you do?
This exercise answers a practical question: is the current pot enough for the call, do you need future opponent money, or would even the maximum payment fall short? Count the outs, calculate their probability and find the minimum extra payment before drawing the conclusion.
All five questions stay the same at every difficulty: outs, success probability, minimum extra payment, maximum extra payment and the conclusion about the call. First master Pot Odds vs Equity; this lesson also prepares the future-payment reasoning used in Set-mining.
1. Read the pot, call and stacks at this decision
Example: the current pot is 31 BB, already including the opponent’s 9 BB bet. Calling costs Hero another 9 BB. Hero has 49 BB left before the call; the opponent has 25 BB left after betting. Hero holds Ah Kh on Qh 7h 2c 3d, with a flush draw.
First count the unseen cards that complete a straight or flush using Hero’s cards. Count a card that completes both draws only once. In the example there are 9 remaining hearts: 9 outs. Pair and overcard improvements are outside this exercise’s success model.
This is a simplified success-or-failure model. It treats completing the indicated draw as a win. It does not calculate equity against a hidden opponent range or ask you to predict how often that opponent will pay.
2. Estimate equity with the Rule of 2
Use the same method as in Pot Odds vs Equity: on the turn, only the river remains, so multiply the outs by 2. This gives an estimated equity percentage, using the same rule at every difficulty.
9 × 2 ≈ 18%
With 4 outs, estimated equity is 8 percent; with 8 outs, 16 percent; with 9 outs, 18 percent. First count the outs, then answer the equity question yourself.
The Rule of 2 is an approximation. Use that same equity estimate throughout the exercise to calculate the minimum future payment and assess the call. The example below uses 18 percent from 9 outs.
3. Find the minimum extra opponent payment
Out of 100 comparable attempts at 18 percent success, 82 lose the 9 BB call: 738 BB lost. The 18 successes therefore need 41 BB of net reward each to cover those losses. The existing pot supplies 31 BB, leaving 10 BB to collect from the opponent on each success.
Maximum of 0 and (9 × (100 − 18) ÷ 18 − 31) = 10 BB
Your current call returns to you when you win; it is not extra profit. If you bet 10 BB on the river and the opponent calls 10 BB, your own river bet also returns. Only the opponent’s extra 10 BB count as new gain in this calculation.
A negative requirement becomes zero. For example, with a 50 BB pot, a 9 BB call and 18 percent success, the current pot already exceeds the 41 BB reward needed; the minimum extra payment is 0 BB.
The minimum must be payable in 0.01 BB units. If the exact threshold is 10.111… BB, 10.11 BB falls short: use 10.12 BB. Round upward once after calculating the threshold.
4. Check how much the remaining stacks allow
After calling 9 BB, Hero’s 49 BB stack leaves 40 BB for the river. The opponent has 25 BB left. A future matched payment can be no larger than the smaller of those two amounts: 25 BB.
Minimum of (49 − 9) and 25 = 25 BB
If Hero instead had 14 BB before calling, only 5 BB would remain. Even against a very deep opponent, Hero could then collect at most 5 extra BB through a matched river bet. Unmatched excess is returned.
5. Conclude what the call requires
The main example needs 10 extra BB and allows up to 25 BB. The answer is a conditional call: you must expect at least 10 extra BB when the draw succeeds. A large stack alone is not enough to choose an automatic call.
| Minimum extra payment (BB) | Maximum extra payment (BB) | Conclusion about the call |
|---|---|---|
| 0 | 25 | Call: no extra payment |
| 10 | 5 | Fold: insufficient payment |
| 10 | 25 | Conditional call |
| 10 | 10 | Conditional call |
At exact break-even, calling and folding have equal EV. If a future payment is needed, reaching that minimum only breaks even; receiving less loses and receiving more gains.
Enough chips do not establish a profitable call. In this example, collecting only 5 BB on success gives 18% × 36 − 82% × 9 = −0.90 BB. Collecting 10 BB breaks even; collecting 15 BB gives +0.90 BB. The required payment is a condition to assess, not a promise from the opponent.
How to practise this exercise
Each round keeps the same turn cards, pot and remaining stacks for all five questions. Calculate the probability instead of reading it as a supplied input. The progress bar preserves your choices; the solution explains the actual numbers and shows the completing outs. Earlier wrong choices do not change later grading. Beginner/easy show numeric substitutions, intermediate symbolic hints, and difficult/nightmare remove the hints.
Timers cover all five questions: 420, 360, 240, 180 and 120 seconds. The four numeric questions have three options in beginner/easy and four in the other difficulties. The last question always offers three call conclusions. The native form also works without JavaScript.